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1s22s22px22py22pz23s23px23py23pz2

1 Answer

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Given :

Electronic configuration of an electron :


1s^2\ 2s^2\ 2p_x^2\ 2p_y^2\ 2p_z^2\ 3s^2 \ 3p_x^2\ 3p_y^2\ 3p_z^2 .

To Find :

The element having such an electronic configuration .

Solution :

We know , the sum of all the power of s and p in all the orbit gives total number of atoms in elements .

So , atomic number is :


Z=2+2+(2+2+2)+2+(2+2+2)\\\\Z=18

Since , the atomic number is 18 .

Therefore , the element is Argon .

Hence , this is the required solution .

User Onel Harrison
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