Answer:
b = 11
11 bricks will be required with 10 (1 inch motar) in between the bricks.
Explanation:
Given the following :
Length of brick = 10 inches long
Between each laid brick, there is an inch of mortar layered before the next brick.
Number of bricks needed to build a wall which is 10 feets long.
Converting from feet to inch :
1 foot = 12 inches
Hence,
10 feets = (10 × 12) = 120 inches (length of wall).
Hence number of bricks needed in each layer :
Total length of b, bricks = length per brick × b = 10b
Since mortar is laid in between any two bricks, then length of mortar for b, number of bricks will be (b-1) inches
Since the total length of wall to be constructed is 120 inches ;
Then the equation required =
Sum of brick length + mortar = 120 inches
10 b + (b - 1) = 120
11b - 1 = 120
Hence,
11b = 120 + 1
11b = 121
b = 121 / 11
b = 11
Number of mortar = (b - 1) = - 11 - 1 = 10
Hence, 11 bricks will be required with 10 (1 inch motar) in between the bricks.