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Find an expression for the square of the orbital period.

User Kros
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1 Answer

4 votes

Answer:

T²= 4π²R³/GM

Step-by-step explanation:

First we know that

Fg= Fc

Because centripetal force must equal gravitational force

So

GMm/R² = Mv²/R

But velocity is 2πR/T

So by substitution we have

GMm/R²= M (2πR/T)/T

We have

T²= 4π²R³/GM as period

User Riken Shah
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