Question

An automobile tire contains air at 320.×103 Pa at 20.0 ◦C. The stem valve is removed and the air is allowed to expand adiabatically against the constant external pressure of 100.×103 Pa until P = Pexternal. Assume the air is an ideal gas with C¯ V = 5/2 R (diatomic). Calculate the final temperature.

Answer 1

6.15.3 k

Step-by-step explanation:

From the question we can see that

q = 0, Δu = w

Then,

`T_f = (C_(V,m)+RP_(ext)P_i)/(C_(V,m)+RP_(ext)P_f) T_i`

putting values wet

=
`(2.5* 8.314+8.314\left(10^5\right)\left(3.20* 10^5\right))/(2.5* 8.314+\left(8.314\right)\left(10^5\right)\left(10^5\right))* \:293`

T_f = 615.3 K