Answer:
The hot resistance of a light bulb is 205.714 ohms.
Step-by-step explanation:
Hot resistance can be found by using Ohm's Law and definition of power, whose expression as a function of power and voltage is:
![R = (V^(2))/(\dot W)](https://img.qammunity.org/2021/formulas/engineering/college/kekzlsad14r3y9wveout6kxvkskjob3qgg.png)
Where:
- Power, measured in Watts.
- Voltage, measured in Volts.
- Resistance, measured in Ohms.
Given that
and
, we find that hot resistance is:
![R = ((120\,V)^(2))/(70\,W)](https://img.qammunity.org/2021/formulas/engineering/college/hnjkyy5ge9sv6doebdccwim4xxuosqdmpu.png)
![R = 205.714\,\Omega](https://img.qammunity.org/2021/formulas/engineering/college/y7f790pz40tcqkb5js12bf0dh9sposbr9k.png)
The hot resistance of a light bulb is 205.714 ohms.