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Find the hot resistance of a light bulb rated 70W, 120V.

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Answer:

The hot resistance of a light bulb is 205.714 ohms.

Step-by-step explanation:

Hot resistance can be found by using Ohm's Law and definition of power, whose expression as a function of power and voltage is:


R = (V^(2))/(\dot W)

Where:


\dot W - Power, measured in Watts.


V - Voltage, measured in Volts.


R - Resistance, measured in Ohms.

Given that
V = 120\,V and
\dot W = 70\,W, we find that hot resistance is:


R = ((120\,V)^(2))/(70\,W)


R = 205.714\,\Omega

The hot resistance of a light bulb is 205.714 ohms.

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