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The greater of two consecutive EVEN numbers is 40 less than twice the smaller number. Find the larger number

1 Answer

3 votes

Answer:

44

Explanation:

z - some integer

2z - first given even integer (the smaller one)

2z+2 - even integer consecutive to 2z (the larger one)

2(2z) - twice the smaller number

2(2z) - 40 - the number 40 less than twice the smaller number

2(2z) - 40 = 2z + 2

4z - 40 = 2z + 2

2z = 42

2z+2 = 42+2 = 44

check:

2(2z)-40 = 2(42)-40 = 84-40 = 44

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