Answer:
![\rho =2.6g/mL](https://img.qammunity.org/2021/formulas/chemistry/college/a8drgvupte01t5q9m1h18w0u5oc383clb2.png)
Step-by-step explanation:
Hello,
In this case, considering that the density is defined as:
![\rho =(m)/(V)](https://img.qammunity.org/2021/formulas/physics/high-school/rij6btep26tvr2ogc8zkdvhjj5rjybl9dh.png)
Thus, since 1 kg equals 1000 g and 1 L equal 1000 mL, the required density in g/mL turns out:
![\rho =(1.7132kg)/(0.65L)*(1000g)/(1kg)*(1L)/(1000mL) \\\\\rho=2.6g/mL](https://img.qammunity.org/2021/formulas/chemistry/college/1bpnk97969lzeqnkbsr6za9ejuw9yvoiul.png)
Take into account that since 0.65 L has two significant figures, the result is also shown with two significant figures.
Regards.