Final answer:
To find the dimensions of a 42 inch TV with a 4:3 aspect ratio, set up a proportion with the aspect ratio and use the Pythagorean theorem. The dimensions are calculated to be 33.6 inches wide and 25.2 inches high.
Step-by-step explanation:
To determine the dimensions of a 42 inch TV with a 4:3 aspect ratio, we first note that the aspect ratio describes the relative dimensions of the width to the height. For a 4:3 aspect ratio, the width is 4 units for every 3 units of height. The diagonal, the TV screen size of 42 inches, forms a right triangle with the width and the height.
We can solve for the width (W) and height (H) using the Pythagorean theorem: W^2 + H^2 = Diagonal^2. Let's set up a proportion using the aspect ratio with W as 4x and H as 3x, where x is a scaling factor we need to determine.
Using the Pythagorean theorem:
(4x)^2 + (3x)^2 = 42^2
16x^2 + 9x^2 = 1764
25x^2 = 1764
x^2 = 1764 / 25
x = sqrt(1764 / 25)
x = sqrt(70.56)
x = 8.4
Now plug the value of x into W and H:
W = 4x = 4(8.4) = 33.6 inches
H = 3x = 3(8.4) = 25.2 inches
Therefore, the dimensions of a 42 inch TV with a 4:3 aspect ratio are 33.6 inches wide by 25.2 inches high.