Question

A car accelerates from 12 m/s to 24 m/s in 6 seconds. Calculate its acceleration.

Answer 1

`\boxed{ \bold{ \huge{ \boxed{ \sf{2 \: m \:/{s} \: ^(2)}}}}}`

Step-by-step explanation:

Initial velocity ( u ) = 12 m/s

Final velocity ( v ) = 24 m/s

Time taken ( t ) = 6

Acceleration of the car = ?

Finding the acceleration

`\boxed{ \sf{acceleration = (v - \: u)/(t)}}`

`\longrightarrow{ \sf{acceleration = (24 - 12)/(6) }}`

`\longrightarrow{ \sf{acceleration = (12)/(6)}}`

`\longrightarrow{ \sf{acceleration = \: 2 \: m/ {s} \: ^(2) }}`

Hope I helped!

Best regards! :D

Answer 2

`\boxed{\sf Acceleration \ (a) = 2 \ m/s^2}`

Given:

Initial velocity (u) = 12 m/s

Final velocity (v) = 24 m/s

Time taken (t) = 6 seconds

To Find:

Acceleration (a) of the car

Step-by-step explanation:

From equation of motion we have:

`\boxed{ \bold{v = u + at}}`

By substituting value of v, u & t in the equation we get:

`\sf \implies 24 = 12 + 6a \\ \\ \sf \implies 6a + 12 = 24 \\ \\ \sf \implies 6a = 24 - 12 \\ \\ \sf \implies 6a = 12 \\ \\ \sf \implies a = (12)/(6) \\ \\ \sf \implies a = 2 \: m {s}^( - 2)`

`\therefore`

Acceleration (a) of the car = 2 m/s²