Distance between the points B= (3,-1) and C= (7,-8) round to the nearest 100

Question

asked Jul 15, 2021 100.0k views

2 Answers

Meenakshi · Answer 1 · 2021-07-15T17:59:06+0000

Answer:

8.06

Step-by-step explanation:

To find the distance between two points, you would use the distance formula.

The distance formula is:

$\sqrt{(x_2-x_1)^(2)+(y_2-y_1)^(2)}$

where (x₁, y₁) and (x₂, y₂) are two points.

Lets plug in the points (3, -1) (x₁, y₁) for (7, -8) for (x₂, y₂):

$\sqrt{(7-3)^(2)+((-8)-(-1))^(2)}$

=
$\sqrt{4^(2)+(-7)^(2)}$

=
√(16+49)

=
√(65)

≈ 8.06225775

Rounded to the nearest hundredth, it is 8.06.

So the distance between the points B and C rounded to the nearest hundredth is 8.06.

I hope you find my answer helpful.