Question

At a painfully loud concert, a 120-dB sound wave travels away from a loudspeaker at 343 m/s.

How much sound wave energy is contained in each 1.0-cm^3 volume of air in the region near this loudspeaker?

Answer 1

2.9*10^-9 J

Step-by-step explanation:

Given that sound level is B= 120dB

And B=10log(Io/I)

And I = (10^12)Io

So I = 1W/m²

So to find Energy

∆E= I∆V/v

Where ∆V= 1*10-6m³

v = 343

So ∆E=2.9*10^-9 J after substituting the values