Question

A cue stick has a mass of 0.5 kg. The cue stick hits a ball with a mass of 0.2 kg at a velocity of 2.5 m/s. What is the velocity of the ball after it is hit?

Answer 1

The moment of impact quick check (connexus academy)

Step-by-step explanation:

Q.Which mathematical representation correctly identifies impulse?

A.impulse=force×time

Q.In a closed system, a ball with a mass of 3 kg and a momentum of 24 kg·m/s collides into a ball with a mass of 1 kg that is originally at rest. Which statement describes the momentum of the balls and the total momentum?

A.The momentum of each ball changes, and the total momentum stays the same.

Q.In a closed system, three objects have the following momentums: 110 kg⋅m/s, −65 kg⋅m/s, and −100 kg⋅m/s. The objects collide and move together. What is the total momentum after the collision?

A.−55 kg⋅m/s

Q.In a closed system, an object with a mass of 1.5 kg collides with a second object. The two objects then move together at a velocity of 50 m/s. The total momentum of the system is 250 kg⋅m/s. What is the mass of the second object?

A.3.5 kg

Q.A cue stick has a mass of 0.5 kg. The cue stick hits a ball with a mass of 0.2 kg at a velocity of 2.5 m/s. What is the velocity of the ball after it is hit?

A.6.3 m/s

Answer 2

1 m/s.

Step-by-step explanation:

Given that,

Mass of a cue stick, m₁ = 0.5 kg

Mass of a ball, m₂ = 0.2 kg

The cue stick hits a ball with a velocity of 2.5 m/s

We need to find the velocity of the ball after it is hit. Tn this problem, the momentum of the system remains conserved. So,

m₁v₁ = m₂v₂

⇒
`v_1=(m_2v_2)/(m_1)\\\\v_1=(0.2* 2.5)/(0.5)\\\\v_1=1\ m/s`

So, the velocity of the ball after it is hit is 1 m/s.