Question

Consider the following Moore’s law growth pattern (since 1980) for the number of transistors inside a particular commercial microprocessor: N = 1920 x 10 0.1637(Y – 1980) where Y is the year and N is the number of transistors. Assuming sustained Moore’s law growth, what will be the number of transistors in a microprocessor in year 2025? Using the same expression, calculate how many years it will take for the transistor count to increase by 100x

Answer 1

No. of transistors =
`$4.1524 * 10^(10)$` transistors

Step-by-step explanation:

Given that:

N =
`$1920 * 10^(0.163(Y-1980))$`

Y = 2025

N =
`$1920 * 10^(0.163(2025-1980))$`

N =
`$4.1524 * 10^(10)$` transistors

Now at Y = 1980

Number of transistors N = 1920

Therefore,

`$1000 = 10^(0.163(Y-1980))$`

`$\log_(10) 1000=0.163(Y-1980)$`

`$(3)/(0.163)=Y-1980$`

18 ≅ 18.4 = Y - 1980

Y = 1980 + 18

= 1998

So, to increase multiples of 1000 transistors. it takes 18 years.