Answer:
V= 124π/3
Explanation:
V=∫πr²dx
This gIves:
=∫π(x+1)²dx
=∫π(x²+2x+1)dx
=π(x³/3+x²+x) |₀⁴
=π(4³/3+4²+4)-π(0³/3+0²+0)
=π(64/3+16+4)
=π(64/3+48/3+12/3)
=π(124/3)=124π/3
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