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_Al2(SO4)3 + __Ca(OH)2 → _Al(OH)3 + _CaSO4
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\qquad\qquad\huge\underline{{\sf Answer}}


\textbf{Let's balance the given equation :}


  • \textsf{First, let's balance the }
    \sf{\: SO_4}
    \textsf{molecule, multiply }
    \sf{ CaSO_4 }
    \textsf{by 3}


  • \textsf{now, let's balance the }
    \sf{\: Ca}
    \textsf{atom, multiply }
    \sf{ Ca(OH)_4}
    \textsf{by 3}


  • \textsf{then, let's balance the }
    \sf{\: Al}
    \textsf{atom, multiply }
    \sf{ Al(OH)_3 }
    \textsf{by 2}

It's all balanced now ~


\sf{Al_2(SO_4)_3 + \boxed3 \: Ca(OH)_2 → \boxed2 \: Al(OH)_3 + \boxed3 \: CaSO_4}

User Louis Strous
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