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10^2+12^2+14^2+......+26^2=??
asked
Jan 3, 2021
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10^2+12^2+14^2+......+26^2=??
Mathematics
college
Dudeldidadum
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1
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Answer:
3156
Explanation:
Used formula:
(1² + 2² + 3² + ... + n²) =1/6*n(n + 1)(2n + 1)
--------
10²+12²+14²+......+26² =
(2*5)²+(2*6)² + (2*7)² + ... + (2*13)² =
4*(5²+6²+7²+...+13²) =
4*(1²+2²+...+13² - (1²+2²+3²+4²)) =
4*(1/6*13(13+1)(2*13+1) - (1+4+9+16)) =
4*(1/6*13*14*27- 30) =
4*(819 - 30) =
4*789 =
3156
Vincentvanjoe
answered
Jan 9, 2021
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Vincentvanjoe
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