Answer:
The inverse of logarithmic function
f⁻¹(x)
Explanation:
Explanation:-
Given f(x) = log₂ˣ ( 2 is a radical)
Let x₁ and x₂ be the ∈ domain f
⇒f(x₁) = f(x₂)
⇒

⇒ x ₁ = x₂
Therefore f(x) is one-one function
Let y = f(x) = log₂ˣ
⇒ y = log₂ˣ
⇒
f(x) is a one-one function and onto
⇒
⇒ f⁻¹(x)
The inverse of logarithmic function
f⁻¹(x)