Answer:
1.) Frictional force = 40N
2.) Vertical force = 294 N
Step-by-step explanation:
Given that a force of (200 N) is applied across a (30 Kg) box, calculate the friction force and the vertical force at (a= 2 m/s2). If the force inclined by 60 degree from the horizontal plane
The given parameters are:
Force F = 200 N
Mass M = 30 kg
Acceleration a = 2 m/s^2
Angle Ø = 60 degree
For the object to move horizontally, the force applied must overcome the frictional force.
But force F = product of mass and acceleration
That is,
FcosØ - fr = ma
Where fr = frictional force.
Substitute all the parameters into the formula
200 cos 60 - fr = 30 × 2
100 - fr = 60
-fr = 60 - 100
Fr = 40 N
Therefore, the frictional force is equal to 40N
The vertical force ( normal force) will be equal to the weight of the body
Weight = mg
Weight = 30 × 9.8
Weight = 294 N