Answer:
4.54×10¯³ mole
Step-by-step explanation:
The following data were obtained from the question:
Volume (V) = 139 mL
Pressure (P) = 760 torr
Temperature (T) = 100 °C
Number of mole (n) =.?
Next, we shall determine convert 139 mL to litre (L). This can be obtained as follow:
1000 mL = 1 L
Therefore,
139 mL = 139 mL / 1000 mL × 1 L
139 mL = 0.139 L
Therefore, 139 mL is equivalent to 0.139 L
Next, we shall convert 760 torr to atm.
This can be obtained as follow:
760 torr = 1 atm
Next, we shall convert 100 °C to Kelvin temperature. This can be obtained as follow:
Temperature (K) = Temperature (°C) + 273
Temperature (°C ) = 100 °C
Temperature (K) = 100 °C + 273
Temperature (K) = 373 K
Finally, we shall determine the number of mole of the vapor as follow:
Volume (V) = 0.139 L
Pressure (P) = 1 atm
Temperature (T) = 373 K
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) =.?
PV = nRT
1 × 0.139 = n × 0.0821 × 373
Divide both side by 0.0821 × 373
n = (1 × 0.139) / (0.0821 × 373)
n = 4.54×10¯³ mole
Therefore, 4.54×10¯³ mole of vapor will fill the flask.