Question

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Michael has 3 quarters, 2 dimes, and 3 nickels in his
pocket. He randomly draws two coins from his pocket,
one at a time, and they are both dimes. He says the
probability of that occurring is because 2 of the 8
coins are dimes. Is he correct? Explain.

Answer 1

Sample Response: No. Choosing two dimes are dependent events. The probability of choosing the first dime is 14 and the probability of choosing the second dime is 17 . The probability that both coins are dimes is (14)(17) = 128.

Answer 2

Answer: Probability = 1/28

Explanation:

First Coin Second Coin

`(2\ dimes)/(8\ total\ coins)* (1\ remaining\ dime)/(7\ remaining\ coins)\quad =(2)/(56)\quad \longrightarrow (1)/(28)(simplified)`