Question

PLS HELP, HAVE A GOOD DAY

Answer 1

• secØcosØ-cos²Ø
• cosØ(secØ-cosØ)
• cosØ(1/cosØ-cosØ)
• cosØ(1-cos²Ø)/cosØ
• 1-cos²Ø
• sin²Ø

Done

Answer 2

`sin^2(\theta)`

Explanation:

Step 1: Take out cos from both sides of the minus

`sec(\theta)\ cos(\theta)-cos^2(\theta)`

`cos(\theta)*(sec(\theta)-cos(\theta))`

Step 2: Convert sec to 1/cos and distribute

`cos(\theta)*((1)/(cos(\theta))-cos(\theta))`

`((1*cos(\theta))/(cos(\theta)))-(cos(\theta)*cos(\theta)})`

`1-cos^2(\theta)`

Step 3: Simplify

`1-cos^2(\theta)` can also be interpreted as
`sin^2(\theta)`

Answer:
`sin^2(\theta)`