Answer:
the 2 solutions are
and
![x=-10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g06044lcauz2ehfx6o3rrlnvokhtpn2f3p.png)
Explanation:
absolute value bars are tricky, they make whatever is inside positive regardless of if it is positive or negative
basically, |x|=|-x|
or |-3|=|3|=3
so one way to solve this is to solve the 2 cases: one where it is positive and one where it is negative
solve these 2 cases:
case1: positive: 3x+12=+18
case2: negative: 3x+12=-18
case1:
![3x+12=18](https://img.qammunity.org/2021/formulas/mathematics/high-school/dczi8chjcfec0j7mw5981ftsmgtp49jmgx.png)
minus 12 both sides
![3x=6](https://img.qammunity.org/2021/formulas/mathematics/high-school/f969ysy9bd0tw93hzd6o00yrx4laglux1h.png)
divide both sides by 3
is one solution
case2:
![3x+12=-18](https://img.qammunity.org/2021/formulas/mathematics/high-school/x5m18yb4qv8sih9tmc9dittwbifvub1v6w.png)
minus 12 both sides
![3x=-30](https://img.qammunity.org/2021/formulas/mathematics/high-school/t1whipl07dauyn1bljpw3mhzfz7v9uml4b.png)
divide both sides by 3
is the other solution
the 2 solutions are
and
![x=-10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g06044lcauz2ehfx6o3rrlnvokhtpn2f3p.png)