2.2 m
tg60° = √3
tg60° = AB/BC
∡DCB = 45° => ΔDBC = isosceles => DB = BC = h
tg60° = (AD + DB)/BC
√3 = (1.6 + h)/h
h√3 = 1.6 + h
h√3 - h = 1.6
h(√3 - 1) = 1.6
h = 1.6/(√3 - 1)
= 1.6/0.73
≈ 2.2 m
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