Question

Please help! algebra 2

Answer 1

c

Explanation:

Let's go one by one.

Reminder before we start anything: i is an imaginary number that equals
`√(-1)` .

Numerator first:

(5 + i)(6 - 5i)

Your first instinct should be to multiply it out to try to get rid of the imaginary numbers, so FOIL:

(5)(6) + (5)(-5i) + (i)(6) + (i)(-5i)

30 - 25i + 6i - 5i²

30 - 19i + 5

35 - 19i

Alright, now the denominator; we just have to distribute:

2i(-3 + 7i)

-6i + 14i²

-14 - 6i

Now we put the numerator and denominator together to get
`(35-19i)/(-14-6i)`.

Unfortunately this doesn't look like any of our answer choices yet, so we have to multiply the top and bottom of the fraction by the conjugate of the denominator to get a real number on the bottom.

What's the conjugate? Well the bottom is -14 - 6i so the conjugate is -14 + 6i.

`(35-19i)/(-14-6i)` ×
`(-14+6i)/(-14+6i)` = c

Answer 2

−47/29+119i/58
I think im sry if its wrong but I believe that is it