Answer:
see below
Explanation:
we have

and the quadratic equation is

so we can see that

and the quadratic formula is
it should go this symbol ± instead of +-
so we insert each value

i don't know if you already know about imaginary numbers if you do then the answer is all the work
if you don't know, well just go until

and say there is no answer to this, because negatives don't have square roots