Question

Y varies directly as x and inversely as z. y=100 when x=5 and z=10. Find y when x=3 and z=60.

Answer 1

10

Explanation:

Formula you are going to use:
`y=(kx)/(z)`

you will use k to help you resolve for y :)

1. 
   `y=(kx)/(z)`
2. 
   `100=(5k)/(10)`
3. 
   `100=(k)/(2)` (multiply by 2 to cancel the fraction)
4. 200 = k

Now you will replace k with 200 :)

1. 
   `y=(kx)/(z)`
2. 
   `y=(3(200))/(60)`
3. 
   `y=(600)/(10)`
4. y = 10

• Hope it helps you
  `:)`