Question

Jenny has some nickels and some

dimes. The value of the coins is $1.65.
There are 12 more nickels than dimes.
How many of each kind of coins does
Jenny have?

Answer 1

19 nickels and 7 dimes

Explanation:

0.05n + 0.10d = 1.65

d+12=n

0.05(d+12) +0.010d = 1.65

0.05d + 0.6 + 0.10d = 1.65

0.15d = 1.05

d = 7 dimes

d+12=n

7+12=n

n = 19 nickels

Answer 2

7 dimes and 19 nickels

Explanation:

d = dimes

n = nickels

The total amount is

.05n + .1d =1.65

He has 12 more nickels than dimes

12+d = n

Substitute this into the first equation

.05 (12 +d) + .1d =1.65

.6 + .05d +.1d = 1.65

Combine like terms

.6 + .15d = 1.65

Subtract .6 from each side

.15d = 1.65-.6

.15d = 1.05

Divide by .15

.15d/.15 = 1.05/.15

d = 7

Now find n

12+d = n

12+7 = n

19 = n