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Write a cubic function that passes through the points (-3,0), (0,0), (1,-8), (2,0)

1 Answer

4 votes
Answer:
y=2x^3+2x^2-6x
Explanation:
y=k(x+3)(x-2) x
∵(1,-8)
∴ -8 = k(1+3)(1-2)1
∴ k=2
∴y=2(x+3)(x-2)x=2x^3+2x^2-6x
User Dlanod
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