Answer:
7/40
Explanation:
probability of taking 7 vehicles from 10 vehicles = 10C₇
number of ways taking 2 SUVs and 5 trucks = 3C₂* 7C₅ = 63
number of ways taking 3 SUVs and 4 trucks =3C₁*7C₄ = 35
number of ways taking 2 SUVs and 5 trucks or 3 SUVs and 4 trucks = 63 + 35 = 98
The probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks or 3 SUVs and 4 trucks is = 98/120 = 49/60
number of ways taking 7 randomly chosen vehicles, exactly 1 is an SUV = 3C₁*7C₆ = 21
The probability that of any 7 randomly chosen vehicles, exactly 1 is an SUV is 21/120 = 7/40