Question

It took a squirrel 0.50\,\text s0.50s0, point, 50, start text, s, end text to run 5.0\,\text m5.0m5, point, 0, start text, m, end text leftward to a nearby tree while maintaining a constant acceleration. The squirrel was running 15\,\dfrac{\text m}{\text s}15 s m ​ 15, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction leftward when it reached the tree.

Answer 1

The squirrel's velocity just before hitting the ground can be determined using the equations of motion.

Step-by-step explanation:

The squirrel's velocity just before hitting the ground can be determined using the equation:

v^2 = u^2 + 2as

Where v is the final velocity, u is the initial velocity (which is 0 m/s in this case), a is the acceleration, and s is the distance traveled. The acceleration can be calculated using the equation:

a = (v - u) / t

Where t is the time taken (which is 0.50 s in this case). Substituting the values into the equations, we can find the squirrel's velocity to be 15 m/s leftward.

Answer 2

-5

Step-by-step explanation:

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