Answer:
see explanation
Explanation:
Using
= i, then i² = (
)² = - 1
and i³ = i² × i = - 1 × i = - i
also
= i² × i² = - 1 × - 1 = 1
We can surmise that i raised to any multiple of 4 will equal 1
Given
( note 35 = 32 + 3 and 32 is a multiple of 4 ), thus
=
![i^(32+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/u6kcmrz3e4vllpw4ptewzm1wzkv7nri8z8.png)
= 1 × i³ = - i