Answer:
(192i +288j -216k) N
Step-by-step explanation:
The un-normalized vector BA is ...
320i +480j -360k
Then the normalized vector is ...
(8i +12j -9k)/√(8² +12² +(-9)²) = (8/17)i +(12/17)j -(9/17)k
The cable tension multiplies this to give the components of cable tension:
(408 N)((8/17)i +(12/17)j -(9/17)k) = (192i +288j -216k) N