Answer:
For the quantity less than one, all the x-values smaller than 4
For the quantity greater than one, all the x-values larger than 4
the value 4 cannot be used at all.
Explanation:
According to the description, the quantity in question can be represented by the fraction:
![(x)/(x-4)](https://img.qammunity.org/2021/formulas/mathematics/college/pjhrcsd6bxba33axt6wi67kyy52uflynsa.png)
Notice that since the binomial (x - 4) is in the denominator, in order to prevent a case with undefined quotient, x - 4 cannot be zero, and that is x cannot be 4.
Notice as well that in the case that x is larger than 4, the binomial (x-4) is a positive number, and in the case that x is less than 4, the binomial (x - 4) is a negative number.
Which values result in the quantity greater than one?
We need to solve for x in the inequality:
![(x)/(x-4) >1](https://img.qammunity.org/2021/formulas/mathematics/college/9f8egg94cda6m7eoenzpnqnh6bwa8mlyfi.png)
So, if x > 4 then we can proceed as follows:
![(x)/(x-4) >1\\x>x-4\\0>-4](https://img.qammunity.org/2021/formulas/mathematics/college/icgtxc4xnm99rjaumerx0yyqbjinpjlg3u.png)
which is a true statement, when x > 4
If x < 4 then:
![(x)/(x-4) >1\\x<x-4\\0<-4](https://img.qammunity.org/2021/formulas/mathematics/college/h4iriy90sk2p7msdfgbb61hqkzagxh2exr.png)
where we have used that (x-4) is negative, so multiplying by it would flip the direction of the inequality. As we see, this case results in an absurd , so it is not possible for x < 4 to render the quantity under study larger than one.
We study similarly the case for the quantity in question being smaller than one considering x > 4:
and we arrive at an absurd. so the quantity cannot be smaller than 1 if x is larger than 4
Now for x smaller than 4:
![(x)/(x-4) <1\\x>x-4\\0>-4](https://img.qammunity.org/2021/formulas/mathematics/college/gl6t7kdciqy15dku3810abcrsck6gj1298.png)
we arrive at a true statement. So it is possible to get the quantity in question smaller that one if x is less than 4.