Answer:
35,250
Explanation:
We divide the interval into 4:
0 ≤ x ≤ 1
1 ≤ x ≤ 2
2 ≤ x ≤ 3
3 ≤ x ≤ 4
The height of each rectangle is evaluated at the midpoint of the interval. So the first rectangle has a height of f(½) = 1500.
The Riemann sum is therefore:
A = (1−0) (1500) + (2−1) (1750) + (3−2) (750) + (43−0) (-750)
A = 3250 liters
The volume increases by 3250 liters, so the final volume is 35,250 liters.