Answer:
ϕ_Net = 2258.87 Nm²/C
Step-by-step explanation:
We are given;
Charge; q = 20 nC = 20 × 10^(-9) C
Length of each side; L = 10 cm = 0.1 m
The net electric flux through one face of the cube is given by the formula;
ϕ_Net = q/ε_o
Where ε_o is a constant known as vacuum of Permittivity and has a value of 8.854 × 10^(−12) C²/N.m²
Thus;
ϕ_Net = (20 × 10^(-9))/(8.854 × 10^(−12))
ϕ_Net = 2258.87 Nm²/C