Question

Studio

2.763 pounds of liquid Z would fill up 5.93 cups. What is the density of liquid Zin g/mL? (1 pound -453.59 grams, 1 cup - 236.59 ml)
.466 g/mL
?
Help
5
2.15 g/mL
6
.558 g/mL
.473 g/mL
7
.893 g/mL

Answer 1

0.895 g/mL

Step-by-step explanation:

Step 1: Given data

Mass of liquid Z (m): 2.763 lb

Volume of liquid Z (V): 5.93 cups

Step 2: Convert "m" to grams

We will use the relationship 1 lb = 453.59 g.

`2.763 lb * (453.59 g)/(1lb) = 1,253g`

Step 3: Convert "V" to milliliters

We will use the relationship 1 cup = 236.59 mL.

`5.93cup * (236.59mL)/(1cup) = 1.40 * 10^(3) mL`

Step 4: Calculate the density of the liquid Z

The density (ρ) of the liquid Z is equal to its mass divided by its volume.

`\rho = (m)/(V) = (1,253g)/(1.40 * 10^(3)mL ) = 0.895 g/mL`