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What is the equation of the line that passes through the point (-6,3) and has a slope of −4/3?

1 Answer

4 votes

Answer:


y = - (4)/(3) x - 5

Explanation:

The standard form for the equation of a line is


y = mx + c

We were told that


y = 3 \: \: \: x = - 6 \: \: \: m = - (4)/(3)

*Note m is the slope*

Therefore


y = mx + c \\ 3 = - (4)/(3) (- 6) + c \\ 3= 8 + c \\ 3 - 8= c \\ - 5 = c

So the answer is


y = - (4)/(3) x - 5

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