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Let f(x)= 2x2−3x+8 What is the value of f(-4)?

User Bricktop
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4.7k points

2 Answers

4 votes

Answer:

f(-4)=52

Explanation:

We are given the function:


f(x)=2x^2-3x+8

We want to find f(-4), so we must substitute -4 in for x.


f(-4)=2(-4)^2-3(-4)+8

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

Evaluate the exponent first.

⇒ (-4)²= -4*-4 = 16


f(-4)=2(16)-3(-4)+8

Multiply 2 and 16.

⇒ 2*16=32


f(-4)=32-3(-4)+8

Multiply -3 and -4.

⇒-3*-4=12


f(-4)=32+12+8

Add the three numbers together.


f(-4)=44+8\\\\f(-4)=52

f(-4) for the function f(x)=2x²-3x+8 is equal to 52

User Vincenza
by
5.1k points
6 votes

Answer:


\displaystyle f(-4) = 52

Explanation:

We are given the function:


f(x)=2x^2-3x+8\\

And we are asked to find f(-4).

To find f(-4), substitute -4 for x. Therefore:



\displaystyle \begin{aligned} f(-4) & = 2(-4)^2-3(-4)+8 \\ \\ & = 2(16) + (12) + 8 \\ \\ & = 32 +12 + 8 \\ \\ & = 52 \end{aligned}

In conclusion:


f(-4) = 52

User Lemnar
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4.8k points