Answer:
A
Explanation:
So we have the equation:
![(1)/(2)(5-2h)=(h)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8djkh5hy4y7ddwxuert6jf72zt3j61r19b.png)
First, let's multiply both sides by 2 to get rid of the fractions. The 2s will cancel. So:
![2((1)/(2)(5-2h))=2((h)/(2))](https://img.qammunity.org/2021/formulas/mathematics/high-school/p3pq2oks3p7l0ufveniy205mp2mmz1rcus.png)
Simplify:
![5-2h=h](https://img.qammunity.org/2021/formulas/mathematics/high-school/7hqri61hiwac9rdbv7r4fb06v06g07fip0.png)
Add 2h to both sides:
![5=3h](https://img.qammunity.org/2021/formulas/mathematics/high-school/pjh1ptvbnzul6h60sak27b1ix6pu9n4ybr.png)
Divide both sides by 3:
![h=5/3](https://img.qammunity.org/2021/formulas/mathematics/high-school/w3sycxk8lng54ao3bmn3qflsejf8hfui0w.png)
Change into mixed fractions:
![h=1(2)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/latcvgdnbung5y0rs6hmzz9thx7lrawpfd.png)
So, our answer is A.
And we're done!
To check, substitute 5/3 back in:
![(1)/(2)(5-2(5/3))=((5/3))/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/smwzhf5w1xrw2thef7j8gf64peiz5kbukf.png)
Multiply and divide:
![(1)/(2)(5-10/3)=(5)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/m1n7l8juf89yfuer0ttgkprsqwaa5k3umk.png)
Subtract on the left:
![(1)/(2)(5/3)=(5)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5crarf1nb68lyhp4h87c9o2pkflfxkymkm.png)
Multiply:
![(5)/(6)\stackrel{\checkmark}{=}(5)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xbgxecr46xd11750s0b47f7a0ljqc24xv6.png)
So, our answer is correct!