Answer:
![y = 46x + 0](https://img.qammunity.org/2023/formulas/mathematics/high-school/hevtfm6yqrjcxyemgg3oupmltkowfc4udz.png)
Explanation:
The equation of a line follows the following format
![y = mx + c](https://img.qammunity.org/2023/formulas/mathematics/high-school/pvq8ckg11f8osopew7ov658g6kwn55gt2t.png)
Note m= the gradient of the line or the slope of the line. To find the gradient it is
![m = (rise)/(run)](https://img.qammunity.org/2023/formulas/mathematics/high-school/cva5aov01qcsb9e7r1r8rd8sieh8uhh7jl.png)
On this graph the
![rise \: = 460 \: \\ and \\ run = 10 \\ \\ m = (460)/(10) \\ m = 46](https://img.qammunity.org/2023/formulas/mathematics/high-school/2swaryhv3g69wu6pttrlrsn4pnue4bej44.png)
After finding the gradient we can now find the equation of the line. We can use any point on the line in order to do this, in that case lets use the point (10, 460)
![y = 460 \: \: \: \: \: \: x = 10 \: \: \: \: \: m = 46\\ y = mx + c \\ 460 = (46)(10) + c \\ 460 = 460 + c \\ 460 - 460 = c \\ 0 = c](https://img.qammunity.org/2023/formulas/mathematics/high-school/pdh8c8v8rfch2hbx113r2puc7ixr3e3177.png)
![y = 46x + 0](https://img.qammunity.org/2023/formulas/mathematics/high-school/hevtfm6yqrjcxyemgg3oupmltkowfc4udz.png)