Question

A famous Hindu mathematician, Aryabhata, showed (in around 500 C.E.) you could add up the first n triangular numbers with a relatively simple formula: n(n + 1)(n + 2) =T + T2 + T3 + ... + Tn 6 Use this fact to find the sum of the first 53 triangular numbers. Answer: The sum of the first 53 square numbers is​

Answer 1

26,235

Explanation:

`T_1 + T_2 + T_3 + ... + T_n = (n(n + 1)(n + 2))/(6)`

`T_1 + T_2 + T_3 + ... + T_(53) = (53(53 + 1)(53 + 2))/(6)`

`T_1 + T_2 + T_3 + ... + T_(53) = 26235`