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What is the product of the expressions? Assume y ≠0 (2y-1/y^2)(3y^2/7)
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What is the product of the expressions? Assume y ≠0 (2y-1/y^2)(3y^2/7)

User Bernhardw
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2 Answers

2 votes

Answer:c

Explanation:

User Studersi
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Answer:

(6y-3)/7

Explanation:

(2y-1/y²)(3y²/7) first simplify 3y²/y² =3

(2y-1)(3/7) =

(6y-3)/7

User Beyers
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