Question

Working with BPDS (Basic Principle for Differences of Squares), apply the Fermat factorization method to factor 5959.

Answer 1

101 and I believe 59

Answer 2

Answer: 101 and 59

Explanation:

Rewrite as a difference of 2 perfect squares

5959 = (6400-441) = (80)^2 - (21)^2

Difference of 2 perfect squares

a^2 - b^2 = (a+b) (a-b)

Factors are (80+21) and (80-21)

101 and 59