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PLEASEEE HELPPP I SUCK AT CHEM :(

a 0.100M H2SO4 solution is neutralised with 10.00ml of a solution of 0.300M KOH


a) write a balanced equation for this reaction

b) what volume of sulfuric acid was neutralised

1 Answer

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Answer:

a) H2SO4 + 2KOH -> 2H2O + K2SO4

b) 9.809 ml

Step-by-step explanation:

Number of Moles = Mass/ Molar Mass

Therefore: Mass = Number of moles * Molar Mass

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Molar mass of H2SO4:

H2= 2.02

S= 32.07

O4= 64

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H2SO4 has the molar mass of 98.09

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the Moles of H2SO4 is given to be 0.100M

Therefore:

Mass= 98.09*0.1

= 9.809g

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Assuming that 1 g= 1 ml, the volume of sulfuric acid is 9.809 ml.

User Johanur Rahman
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