Question

Se infla un globo de helio hasta el volumen de 0.045 m3 a la temperatura de 2°C Sí el globo se enfría a -12 °C . ¿Cuál será su nuevo volumen? Considere que la presión no varía

Answer 1

Hi! the english version of the given question is "A helium balloon is inflated to the volume of 0.045 m3 at a temperature of 2 ° C. If the balloon is cooled to -12 ° C. What will its new volume be? Consider that the pressure does not vary". The answer is given in english.

Answer:

The new volume of balloon is
`0.043\;m^(3)`.

Step-by-step explanation:

Let's assume the helium gas inside the balloon behaves ideally.

The total number of moles of helium gas inside the balloon remains constant.

Applying combined gas law, we get:

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`

Where:

`P_(1)\;and\;P_(2)` are the initial and final pressure of the balloon respectively.

`V_(1)\;and\;V_(2)` are the initial and final volume of the balloon respectively.

`T_(1)\;and\;T_(2)` are the initial and final temperature in the kelvin scale respectively.

Given:

`P_(1)=P_(2)`

`V_(1)=0.045\;m^(3)`

`T_(1)=(273+2)\;K=275\;K`

`T_(2)=(273-12)\;K=261\;K`

Substituting the above values, we get:

`((0.045\;m^(3)))/(275\;K)=(V_(2))/(261\;K)`

`\Rightarrow V_(2)=0.043\;m^(3)`