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Determine the number of carbon atoms in 1.00 kg of carbon dioxide.

____X 10__atoms(Enter your answer in scientific notation.)

Determine the number of oxygen atoms in 1.00 kg of carbon dioxide.
____X 10__atoms (Enter your answer in scientific notation.)

Calculate the mass of potassium nitrate that contains 1.00 mol of oxygen atoms.
_____g





—Pls show steps!! I’m so confused and need help—

User Kreetchy
by
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2 Answers

1 vote

Answer:

1. 1.37 * 10^25 atoms of carbon

2. 2.74 * 10^25 atoms of oxygen

3. 33.67g of Potassium Nitrate

Step-by-step explanation:

2. Firstly, we want to know the number of atoms of oxygen in 1 kg of carbon dioxide.

Firstly, we will need to know the number of moles of carbon iv oxide in 1kg of carbon iv oxide

Mathematically;

number of moles = mass/molar mass

molar mass of carbon iv oxide is 44 g/mol

mass here is 1000g (1kg is 1000g)

So the number of moles of CO2 in 1kg of CO2 will be; 1000/44 = 22.73 moles

Now 1 mole of CO2 contains 2 atoms of oxygen, thus 1 mole of CO2 contains 2 moles of oxygen

So the number of moles of oxygen in 1kg CO2 will be 2 * 22.73 = 45.46 moles

Mathematically, 1 mole contains 6.02 * 10^23 atoms

So 45.46 moles will contain =

6.02 * 10^23 * 45.46 = 2.74 * 10^25 atoms of oxygen

1. 1 mole of co2 contains 1 atom of carbon , thus, 1 mole of CO2 will

contain 1 mole of carbon

From above, 1kg of carbon iv oxide contains 22.73 moles , thus 1kg of carbon iv oxide will contain 22.73 moles of carbon too

So the number of atoms will be 22.73 * 6.02 * 10^23 = 1.37 * 10^25 atoms

3. Mass of KNO3 that contains 1 mole of oxygen atom

From the formula of the compound, we can see that 1 mole of KNO3 contains 3 atoms of oxygen which translates to 3 moles of oxygen

So 1 mole of oxygen will translate to 1/3 mole of KNO3

Mathematically;

mass = number of moles * molar mass

Molar mass of KNO3 = 39 + 14 + 3(16) = 39 + 14 + 48 = 101 g/mol

So the mass will be = 1/3 * 101 = 33.67g

User Tasmin
by
4.7k points
7 votes

Answer:

1.37x10²⁵atoms of carbon

2.74x10²⁵ atoms of oxygen.

33.7g of KNO₃

Step-by-step explanation:

To answer this question you must use molar mass of carbon dioxide (44g/mol) and 1 mole are 6.022x10²³atoms.

1.00kg are 1000g of CO₂. Moles are:

1000g CO₂ * (1mol / 44g) = 22.73 moles of CO₂ = 22.73 moles of carbon.

In atoms:

22.73 moles C * (6.022x10²³atoms / 1mole) = 1.37x10²⁵atoms of carbon

There are 22.73 moles of CO₂ * 2 = 45.45 moles of oxygen are present in the carbon dioxide. In atoms:

45.45 moles Oxygen * (6.022x10²³atoms / 1mole) = 2.74x10²⁵ atoms of oxygen.

1 mole of Potassium nitrate, KNO₃, contains 3 moles of oxygen. 1 mol of oxygen are:

1.00 mol O * (1mol KNO₃ / 3 moles O) = 0.33 moles of KNO₃

As molar mass of KNO₃ is 101.1g/mol:

0.33 moles of KNO₃ * (101.1g / mol) = 33.7g of KNO₃

User Raduw
by
4.9k points