Question

15 points! The data set shows the weights of pumpkins, in pounds, that are chosen for a photograph in a farming magazine. The rest of the question is on the screenshot. Please help!

Answer 1

Explanation:

a). Mean of the given data set =
`(32+28+18+40+22)/(5)`

= 28

b). x
`x-\overline{x}`
`(x-\overline{x})^2`

32 32-28 = 4 16

28 28 - 28 = 0 0

18 18 - 28 = -10 100

40 40 - 28 = 12 144

22 22 - 28 = -6 36

`\sum({x-\overline x})^2` = 296

c). Standard deviation =
`\sqrt{\frac{\sum (x-\overline{x})^2}{n}}`

=
`\sqrt{(296)/(5) }`

= 7.69

d). Mean of the new set of weights =
`(32+33+34+35+36)/(5)`

= 34

Since mean of the data set is more close to each data, standard deviation will be less than the deviation given in part (c).