Question

Find an equation of the line L that passes through the point

(−2, 6)
and satisfies the given condition. (Let x be the independent variable and y be the dependent variable.)
L is perpendicular to the line
2x + 5y = 10

Answer 1

y = 5/2x + 11

Explanation:

If a line is perpendicular to another it's slope is a negative reciprocal

First let's solve for y in the equation that l is perpendicular to

2x + 5y = 10

5y = -2x + 10

y = -2/5x + 2

Now the slope of L is 5/2

Next let's find the y-intercept on L

y = 5/2x + b

To do plug (-2,6) into the equation

6 = -5 + b

b = 11

y = 5/2x + 11