Question

What is the answer (7t2+4t+1)–4t2

Answer 1

`\boxed{ \bold{ \huge{ \boxed{ \sf{3 {t}^(2) + 4t + 1}}}}}`

Explanation:

`\sf{ (7 {t}^(2) + 4t + 1) - 4 {t}^(2) }`

Remove the unnecessary parentheses

`\longrightarrow{ \sf{7 {t}^(2) + 4t + 1 - 4 {t}^(2) }}`

Collect like terms

`\longrightarrow{ \sf{7 {t}^(2) - 4 {t}^(2) + 4t + 1}}`

`\longrightarrow{ \sf{3 {t}^(2) + 4t + 1}}`

Hope I helped!

Best regards! :D