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2 votes
Find a quadratic equation whose roots are
3-
√(3) and 3 +√(3)

1 Answer

5 votes

Answer:

x² - 6x + 6 = 0

Explanation:

Given the roots are x = 3 -
√(3) and x = 3 +
√(3) , then the corresponding factors are

(x - (3 -
√(3) ) ) and (x - (3 +
√(3) ) ), that is

(x - 3 +
√(3) ) and (x - 3 -
√(3) )

The equation is then the product of the factors

(x - 3 +
√(3) )(x - 3 -
√(3) ) = 0

(x - 3)² - (
√(3) )² = 0

x² - 6x + 9 - 3 = 0

x² - 6x + 6 = 0

User Zou Jeff
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